Just to let off some steam, after working on my math assignment for the past two hours!, I'm gonna share with you my accomplishment. Don't worry, you don't have to read or understand it, it will make me feel better though!

20a.) The student is correct to put the 3 over the hundreds place, the 1, because 7 isn’t going into 2, it’s going into 21. However, the student forgot to follow suit with the 49. 7 is not going into 4, it can’t, it’s going into 49, and should then be put over the 9, giving an answer of 307.

b.) Firstly, the student forgot to put the 2 over the 13, not just the 1, because 4 is going into 13, not 1. Additionally, 4 can go into 13 four times, to equal 12 with a remainder of 1.

50a.) 24 x 11 = 264, 14 x 11 = 154, 62 x 11 = 682. I seems that when a two digit number is multiplied by 11, the product is a thee digit number, whose first and last digit are that of the original number, and whose middle number is the sum of the first and second number.

b.) If you replace the two digit number by ab and plug it into the equation, it becomes clear why this happens, and that is holds true for any two digit number. :

A lot of the graphs wouldn't show up... so that's that. have a great chag.